When aqueous solution of borax is acidified with hydrochloric acid, a white crystalline solid is for

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p-Block Elements - I

medium

When aqueous solution of borax is acidified with hydrochloric acid, a white crystalline solid is formed which is soapy to touch. Is this solid acidic or basic in nature ? Explain.

Option A

Option B

Option C

Option D

Solution

An aqueous solution of borax is acidified with $\mathrm{HCl}$ to give boric acid.

$\mathrm{Na}_{2} \mathrm{~B}_{4} \mathrm{O}_{7}+2 \mathrm{HCl}+5 \mathrm{H}_{2} \mathrm{O} \rightarrow 2 \mathrm{NaCl}+4 \mathrm{H}_{3} \mathrm{BO}_{3}$

Boric acid is a weak monobasic acid. It is not a protonic acid but acts as a Lewis acid by accepting electrons from a hydroxyl ion :

$\mathrm{B}(\mathrm{OH})_{3}+2 \mathrm{HOH} \rightarrow\left[\mathrm{B}(\mathrm{OH})_{4}\right]^{-}+\mathrm{H}_{3} \mathrm{O}^{+}$

Standard 11

Chemistry

Borax is converted into crystalline boron by the following steps

${B{orax}}\xrightarrow{X}{H_3}B{O_3}\xrightarrow{\Delta }{B_2}{O_3}\xrightarrow[\Delta ]{Y}B$,

$X$ and $Y$ are respectively

normal

Consider the compounds, $BCl_3$, and $CCl_4$ How will they behave with water ? Justify.

easy

$Na _2 B _4 O _7 \stackrel{\text { heat }}{\longrightarrow} X + NaBO _2$
in the above reaction the product " $X$ " is :

medium

(NEET-2022)

Diborane $(B_2H_6)$ reacts independently with $O_2$ and $H_2O$ to produce, respectively

hard

(JEE MAIN-2019)

Assertion : Coloured cations can be identified by borax bead test.

Reason : Transparent bead $(NaBO_2 + B_2O_3)$ forms coloured bead with coloured cation.

medium

(AIIMS-2009)

When aqueous solution of borax is acidified with hydrochloric acid, a white crystalline solid is formed which is soapy to touch. Is this solid acidic or basic in nature ? Explain.

Solution

Similar Questions

Borax is converted into crystalline boron by the following steps ${B{orax}}\xrightarrow{X}{H_3}B{O_3}\xrightarrow{\Delta }{B_2}{O_3}\xrightarrow[\Delta ]{Y}B$, $X$ and $Y$ are respectively

Consider the compounds, $BCl_3$, and $CCl_4$ How will they behave with water ? Justify.

$Na _2 B _4 O _7 \stackrel{\text { heat }}{\longrightarrow} X + NaBO _2$ in the above reaction the product " $X$ " is :

Diborane $(B_2H_6)$ reacts independently with $O_2$ and $H_2O$ to produce, respectively

Assertion : Coloured cations can be identified by borax bead test. Reason : Transparent bead $(NaBO_2 + B_2O_3)$ forms coloured bead with coloured cation.

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Borax is converted into crystalline boron by the following steps

${B{orax}}\xrightarrow{X}{H_3}B{O_3}\xrightarrow{\Delta }{B_2}{O_3}\xrightarrow[\Delta ]{Y}B$,

$X$ and $Y$ are respectively

$Na _2 B _4 O _7 \stackrel{\text { heat }}{\longrightarrow} X + NaBO _2$
in the above reaction the product " $X$ " is :

Assertion : Coloured cations can be identified by borax bead test.

Reason : Transparent bead $(NaBO_2 + B_2O_3)$ forms coloured bead with coloured cation.